6 replies to this topic

[SpacemanDan]

Is there any way to find out how many parts/heads a boss has and when one part/head is defeated?

[Joe123]

CODE

int moldormcount;
for(int i=1;i<=Screen->NumNPCs();i++){
    npc e = Screen->LoadNPC(i);
    if(e->ID == NPC_MOLDORM) moldormcount++;
}

Assuming each piece of the boss is a seperate npc.
Which I think it is.

[Gleeok]

Good luck figuring that out. What I would do is probably use a

CODE

Trace(Screen->NumNPCs());

You could probably crash the engine or some other odd behavior by modifying the various attributes of "dead" enemies like gleeok heads. ...well maybe the new builds are better about that stuff.

[Joe123]

What's wrong with it?
Returns the number of moldorm pieces left on the screen...

I'll make it into an integer if you want.
Look.

CODE

int moldormcount();
    int a;
    for(int i=1;i<=Screen->NumNPCs();i++){
        npc e = Screen->LoadNPC(i);
        if(e->ID == NPC_MOLDORM) a++;
    }
    return a;
}

Happy now?

[Gleeok]

Huh? I was mainly talking aboutr gleeoks. They're handled different I believe.

[SpacemanDan]

Thank you! I appreciate the help! This'll help a great deal!

But I wasn't aware that Gleeoks might be handled differently.

[Joe123]

Oh sorry, I thought you meant my code was very complicated or something.